When \( a \ne 0 \), there are two solutions to \(ax^2 + bx + c = 0\) and they are:
$$ x = {-b \pm \sqrt{b^2-4ac} \over 2a} $$
$$
\begin{aligned}
\dot{x} & = \sigma(y-x) \
\dot{y} & = \rho x - y - xz \
\dot{z} & = -\beta z + xy
\end{aligned}
$$
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